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In triangleABC, If (b+c)/(11)=(c+a)/(12)...

In `triangleABC`, If `(b+c)/(11)=(c+a)/(12)=(a+b)/(13)`, then `cosC=`

A

`(5)/(7)`

B

`(7)/(5)`

C

`(16)/(17)`

D

`(17)/(16)`

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A
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