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In triangleABC, a cosB-b cosA=...

In `triangleABC, a cosB-b cosA=`

A

`(a^(2)-b^(2))`

B

`b^(2)-c^(2)`

C

`c^(2)-a^(2)`

D

`a^(2)+b^(2)+c^(2)`

Text Solution

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The correct Answer is:
A
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