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In triangleABC, (b+c)cosA+(c+a)cosB+(a+b...

In `triangleABC, (b+c)cosA+(c+a)cosB+(a+b)cosC=`

A

`a+b+c`

B

`2(a+b+c)`

C

`(a+b+c)/(2)`

D

`(a+b+c)/(4)`

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