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IN triangleABC, (cosC+cosA)/(c+a)+(cosB)...

IN `triangleABC, (cosC+cosA)/(c+a)+(cosB)/(b)=`

A

`(1)/(a)`

B

`(1)/(b)`

C

`(1)/(c)`

D

`(a+b)/(b)`

Text Solution

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The correct Answer is:
B
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