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In triangleABC, a^(2)sin(B-C)=...

In `triangleABC, a^(2)sin(B-C)=`

A

`(b^(2)-c^(2))sinA`

B

`(c^(2)-b^(2))sinA`

C

`(2b^(2)-c^(2))sinA`

D

`2(c^(2)-b^(2))sinA`

Text Solution

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The correct Answer is:
A
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