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In a DeltaABC, cosecA(sinBcosC+cosBsinC)...

In a `DeltaABC`, cosecA(sinBcosC+cosBsinC)` is equal to

A

`1`

B

`(a)/(c)`

C

`(c)/(a)`

D

`(c)/(ab)`

Text Solution

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The correct Answer is:
A
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