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In triangleABC, (a+b-c)tan((C)/(2))=...

In `triangleABC, (a+b-c)tan((C)/(2))=`

A

`(A(triangleABC))/(s)`

B

`(2A(triangleABC))/(s)`

C

`A(triangleABC)`

D

`2A(triangleABC)`

Text Solution

Verified by Experts

The correct Answer is:
B
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