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In any triangle ABC cotA/2,cotB/2,cotc/2...

In any `triangle ABC` `cotA/2,cotB/2,cotc/2` are in A.P. then

A

`((a+b+c)/(b+c-a))cot((A)/(2))`

B

`((b+c-a)/(a+b+c))cot((A)/(2))`

C

`((a+b+c)/(b+c-a))tan((A)/(2))`

D

`((b+c-a)/(a+b+c))tan((A)/(2))`

Text Solution

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The correct Answer is:
A
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