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NIKITA PUBLICATION-TRIGONOMETRIC FUNCTIONS-MCQs
- tan^-1 sqrt3-sec^-1(-2)=pi/3
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- tan^(-1)(1)+cos^(-1)((1)/(2))+sin^(-1)((1)/(2))=
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- cos^(-1)sqrt(1-x)+sin^(-1)sqrt(1-x)=
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- cos^(-1)((3)/(5))+cos^(-1)((4)/(5))=
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- The value of sin^(-1)((2sqrt(2))/(3))+sin^(-1)((1)/(3)) is
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- The value of sin(sin^(-1)1/2+cos^(-1)1/2)=?
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- (tan^(- 1)(sqrt(3))-sec^(- 1)(-2))/(cosec^(- 1)(-sqrt(2))+cos^(- 1)(-1...
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- Find the value of tan^(-1)(x/y)-tan^(-1)((x-y)/(x+y))
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- निम्नलिखित फलनों को सरलतम रूप में लिखिए : tan^(-1)""((cos x-sinx)/(c...
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- Show that tan^(-1)[(cosx+sinx)/(cosx-sinx)]=(pi)/(4)+x.
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- tan^(-1)""[(a cos x -b sinx)/(b cosx+a sinx)] को सरल कीजिए, यदि ""(a)...
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- Differentiate w.r.t. x: (i)tan^(-1){sqrt((1+cosx)/(1-cosx))}" "(...
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- If tan^(-1) y = tan^(-1) x + tan^(-1)((2x)/(1 -x^(2)))", where" |x| lt...
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- If tan^(-1)x-tan^(-1)y=tan^(-1)A, then A=
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- If x takes negative permissible vlaue then sin^(-1)x=
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- Differentiate each of the following functions with respect to x : si...
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- If x in[0, 1], then (1)/(2)cos^(-1)((1-x)/(1+x))=
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- Prove that : tan1/2{sin^(-1)(2x)/(1+x^2)+cos^(-1)(1-y^2)/(1+y^2)}=(x+y...
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- Solve y=tan^(-1)((sqrt(1+x^2)-1)/x)
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- tan^(- 1)((sqrt(1+x)+sqrt(1-x))/(sqrt(1+x)-sqrt(1-x)))
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