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Find the cartesian equation of the line...

Find the cartesian equation of the line which passes through the point `(-2,4,-5)` and parallel and line are `(3,5,6)`. So, the equation of line is,
`(x-(-2))/(3) = (y-4)/(5) = (z-(-5))/(6)`.

A

`(x-2)/3 = (y+4) = (z-5)/6`

B

`(x+2)/3 = (y-4)/5 = (z+5)/6`

C

`(x-2)/3 = (y+3)/5 = (z+5)/6`

D

`(x+2)/3 = (y+4)/5 = (z+5)/6`

Text Solution

Verified by Experts

The correct Answer is:
B
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