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The point of intersection of the lines `(x-5)/3=(y-7)/(-1)=(z+2)/1a n d=(x+3)/(-36)=(y-3)/2=(z-6)/4` is a. `(21 ,5/3,(10)/3)` b. `(2,10 ,4)` c. `(-3,3,6)` d. `(5,7,-2)`

A

(2,10,4)

B

(-3,3,6)

C

`(5,7,-2)`

D

`(21,5/3, 10/3)`

Text Solution

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The correct Answer is:
D
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The point of intersection of the lines (x-5)/3=(y-7)/(-1)=(z+2)/1 and (x+3)/(-36)=(y-3)/2=(z-6)/4 is (A) (21, 5/3, 10/3) (B) (2,10,4) (C) (-3,3,6) (D) (5,7,-2)

The point of intersection of the lines (x-5)/(3)=(y-7)/(-1)=(z+2)/(1) and (x+3)/(-36)=(y-3)/(2)=(z-6)/(4) is (A) (21,(5)/(3),(10)/(3))(B)(2,10,4)(C)(-3,3,6)(D)(5,7,-2)

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Prove that the lines (x+1)/(3)=(y+3)/(5)=(z+5)/(7) and (x-2)/(1)=(y-4)/(4)=(z-6)/(7) lines.

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