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Prove that the shortest distance between...

Prove that the shortest distance between the diagonals of a rectangular parallelopiped whose coterminous sides are a, b, c and the edges not meeting it are

A

`(bc)/sqrt(b^(2) + c^(2))`

B

`(ca)/sqrt(c^(2) + a^(2))`

C

`(ab)/sqrt(a^(2) + b^(2))`

D

`(abc)/sqrt(a^(2) + b^(2) + c^(2))`

Text Solution

Verified by Experts

The correct Answer is:
C
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