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Perpendicular are drawn from points on the line `(x+2)/(2)=(y+1)/(-1)=(z)/(3)` to the plane `x+y+z=3`. The feet of perpendiculars lie on the line.

A

`(x)/(2)=(y-1)/(-7)=(z-2)/(-5)`

B

`(x)/(2)=(y-1)/(7)=(z-2)/(5)`

C

`(x)/(2)=(y-1)/(-7)=(z-2)/(5)`

D

`(x)/(2)=(y-1)/(7)=(z-2)/(-5)`

Text Solution

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The correct Answer is:
C
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