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The point on the curve y= sqrt(x-1) ...

The point on the curve ` y= sqrt(x-1)` where the tangent is perpendicular to the line `2x+y-5=0` is

A

`(2, -1)`

B

`(10, 3)`

C

`(2, 1)`

D

`(5, -2)`

Text Solution

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The correct Answer is:
C
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