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If int(0)^(pi//2) log(cosx) dx=pi/2 log ...

If `int_(0)^(pi//2) log(cosx) dx=pi/2 log (1/2),` then
`int_(0) ^(pi//2) log (sec x ) dx = `

A

`(pi)/(2)log((1)/(2))`

B

`1-(pi)/(2)log((1)/(2))`

C

`1+(pi)/(2)log((1)/(2))`

D

`(pi)/(2)log2`

Text Solution

Verified by Experts

The correct Answer is:
D
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