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The equation of tangent to the curve y=3...

The equation of tangent to the curve `y=3x^(2)-x+1` at (1,3) is

A

`y=5x+2`

B

`y=5x-2`

C

`y=(x)/(5)+2`

D

`y=(x)/(2)-2`

Text Solution

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The correct Answer is:
B
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Find the equation of the tangent to the curve y=3x^(2)-x+1 at P(1, 3).

Find the equation of the tangent of the curve y=3x^(2) at (1, 1).

Knowledge Check

  • The equation of tangent to the curve y=x^(3)-x^(2)-1 at the point whose absicissa is -2 is

    A
    16x-y+19=0
    B
    16x-y=19
    C
    16x+y+19=0
    D
    16x+y=19
  • The equation of tangent to the curve x^(2)+y^(2)+xy=3 at (1,1) is

    A
    x+y-2=0
    B
    x-y+2=0
    C
    x-y-2=0
    D
    x+y+2=0
  • The equation of tangent to the curve 2x^(2)+3y^(2)-5=0 at (1,1) is

    A
    2x+3y+5=0
    B
    2x-3y-5=0
    C
    2x-3y+5=0
    D
    2x+3y-5=0
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