Home
Class 12
MATHS
The side of a square is increasing at th...

The side of a square is increasing at the rate of 0.5 cm/sec. Find the rate of increase of its area, when the side of square is 20 cm long.

A

`1cm^(2)//sec`

B

`10 cm^(2)//sec.`

C

`40 cm^(2)//sec`

D

`20 cm^(2)//sec`

Text Solution

Verified by Experts

The correct Answer is:
D
Promotional Banner

Topper's Solved these Questions

  • APPLICATION OF DEFINITEINTEGRAL

    NIKITA PUBLICATION|Exercise MULTIPLE CHOICE QUESTIONS:(MCQ)|27 Videos

  • BINOMIAL DISTRIBUTION

    NIKITA PUBLICATION|Exercise MCQS|77 Videos

Similar Questions

Explore conceptually related problems

The side of a square is increasing at a rate of 4cm/sec. Find the rate of increase of its area when the side of square is 10 cm.

The side of a square is increasing at the rate of 0.1cm/sec. Find the rate of increase of its perimeter.

The side of a square is increasing at a rate of 3 cm/sec. Find the rate of increasing of its perimeter when the side of square is 5cm.

The area of a square is increasing the rate of 0.5" cm"^(2)//"sec" . Find the rate of increase of its perimeter when the side of square is 10 cm long.

The side of a square in increasing at the rate of 0.2cm/sec. Find the rate of increase of the perimeter of the square.

The radius of a circle is increasing at the rate of 0.5cm/sec. Find the rate of increase of its circumference.

The side of a square is increasing at the rate of 0.2 cm/s. The rate of increase of perimeter w.r.t time is :

If the length of the diagonal of a square is increasing at the rate of 0.2 cm/sec, then the rate of increase of its area when its side is 30//sqrt(2) cm, is

The side of a square is increasing at ther rate of 0.2 cm//s . The rate of increase of perimeter w.r.t. time is :

The radius of a circular plate is increasing at the rate of 0.01 cm/sec. The rate of increase of its area when the radius is 12 m

NIKITA PUBLICATION-APPLICATIONS OF DERIVATIVES-MULTIPLE CHOICE QUESTIONS
  1. The sides of an equilateral triangle are increasing at the rate of ...

    Text Solution

    |

  2. The length x of a rectangle is increasing at the rate of 3 cm/sec. and...

    Text Solution

    |

  3. The side of a square is increasing at the rate of 0.5 cm/sec. Find the...

    Text Solution

    |

  4. The sides of a square area is increasing at the rate of 0.5 cm/sec. If...

    Text Solution

    |

  5. A square plate is contracting at the uniform rate of 2 cm^(2)//sec. If...

    Text Solution

    |

  6. If the rate of change of area of a square plate is equal to that of th...

    Text Solution

    |

  7. The diagonal of square is changing at the rate of 0.5 cms^(-1). Then t...

    Text Solution

    |

  8. The edge of a cube is decreasing at the rate of 0.04 cm/sec. If the ed...

    Text Solution

    |

  9. एक घन के आयतन 8 cm ^3 //s की दर से बढ़ रहा है पृष्ठ क्षेत्रफल किस द...

    Text Solution

    |

  10. If the radius of a circle is 2 cm and is increasing at the rate of 0.5...

    Text Solution

    |

  11. Find the rate of change of the area of a circular disc with respect...

    Text Solution

    |

  12. The radius of a circular blot of oil is increasing at the rate of 2 cm...

    Text Solution

    |

  13. The radius of a circular blot of oil is increasing at the rate of 2 cm...

    Text Solution

    |

  14. A stone is dropped into a pond. Waves in the form of circles are gener...

    Text Solution

    |

  15. A stone is dropped into a pond. Waves in the form of circles are gener...

    Text Solution

    |

  16. If the rate of increase of area of a circle is not constant but the ra...

    Text Solution

    |

  17. The radius of a soap bubble is increasing at the rate of 0.2 cm/sec. I...

    Text Solution

    |

  18. A spherical soap bubble is expanding so that its radius is increasing ...

    Text Solution

    |

  19. एक गुब्बारा जो सदैव गोलाकार रहता है का परिवर्तन व्यास 3/2(2x+1) है x क...

    Text Solution

    |

  20. A spherical snow ball is melting so that its volume is decreasing at t...

    Text Solution

    |