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The point on the curve y= sqrt(x-1) ...

The point on the curve ` y= sqrt(x-1)` where the tangent is perpendicular to the line `2x+y-5=0` is

A

(2,-1)

B

(10, 3)

C

(2,1)

D

(5,-2)

Text Solution

Verified by Experts

The correct Answer is:
C
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