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NIKITA PUBLICATION-DEFINITE INTEGRAL-MULTIPLE CHOICE QUESTIONS
- Evaluate : int(pi/3)^(pi/4)(tanx+cotx)^2dx
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- int0^(2pi) |sin^3theta|d theta
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- Evaluate : (i) int(0)^(pi//2)cos^(3)xdx (ii) int(0)^(pi//2)sin^(4)xdx
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- int(0)^(pi//2) sin^(4) x " " dx =
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- int(0)^(pi//2) cos^(5) x " " dx=
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- int (0) ^(pi//4) tan^(2) x " " dx=
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- Evaluate: int0^(pi//4)sqrt(1+sin2x)dx (ii) int0^(pi//4)sqrt(1-sin2x...
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- Evaluate: int(pi//4)^(pi//2)sqrt(1-sin2x)dx
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- int (0) ^(pi//2) sqrt(1-cos x )" "dx=
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- int (0) ^(pi//2) (sin x +cos x)/ sqrt(1+sin 2x )" "dx=
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- int(0)^(pi) dx/(1-sin x)=
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- int(-pi//4)^(pi//4) dx/(1+sin x)=
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- int(-pi//4)^(pi//4) dx/(1-sin x)=
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- int (0)^(pi//2)(dx)/(1+ cos x)
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- The greater of int(0)^(pi//2)(sinx)/x dx and pi/2 is
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- Evaluate : (i) int(0)^(pi//2)(cosx)/((cos.(x)/(2)+sin.(x)/(2)))dx (ii)...
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- int(pi//4) ^(pi//2) (cos theta)/((cos (theta/2) + sin (theta/2))^(3))d...
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- int(0)^(pi//2) (sin^(2)theta)/ (1+cos theta)^(2) d theta =
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- int(0)^(pi//4)(tan^(3)x)/((1+cos2x))dx
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- int(0)^(pi//2) (cosx)/(3cos x+ sin x ) dx=
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