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int(0)^(pi//2) sin^(4) x " " dx =...

`int_(0)^(pi//2) sin^(4) x " " dx =`

A

`(3pi)/8`

B

`(3pi)/16`

C

`(3pi)/3`

D

`(3pi)/32`

Text Solution

Verified by Experts

The correct Answer is:
B
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