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NIKITA PUBLICATION-DEFINITE INTEGRAL-MULTIPLE CHOICE QUESTIONS
- int (0) ^(pi//2) sqrt(1-cos x )" "dx=
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- int (0) ^(pi//2) (sin x +cos x)/ sqrt(1+sin 2x )" "dx=
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- int(0)^(pi) dx/(1-sin x)=
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- int(-pi//4)^(pi//4) dx/(1+sin x)=
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- int(-pi//4)^(pi//4) dx/(1-sin x)=
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- int (0)^(pi//2)(dx)/(1+ cos x)
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- The greater of int(0)^(pi//2)(sinx)/x dx and pi/2 is
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- Evaluate : (i) int(0)^(pi//2)(cosx)/((cos.(x)/(2)+sin.(x)/(2)))dx (ii)...
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- int(pi//4) ^(pi//2) (cos theta)/((cos (theta/2) + sin (theta/2))^(3))d...
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- int(0)^(pi//2) (sin^(2)theta)/ (1+cos theta)^(2) d theta =
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- int(0)^(pi//4)(tan^(3)x)/((1+cos2x))dx
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- int(0)^(pi//2) (cosx)/(3cos x+ sin x ) dx=
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- int(0)^(pi//2)(sqrt(tanx)+sqrt(cotx))dx
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- int1^3cos(logx)/x dx
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- int(0)^(pi//2) sin ^(3) x cos^(3) x" "dx =
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- int(0)^(pi//2) sin ^(2) x cos^(3) x" "dx =
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- int0^(pi/2)sqrt(sinphi)cos^5phidphi
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- int(0)^(pi//2) sqrt(cos x) sin ^(3) x" "dx=
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- int0^pisin^3x(1+2cosx)(1+cosx)^2dx
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- int(0)^(pi//4) sec^(4) x" dx =
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