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NIKITA PUBLICATION-DEFINITE INTEGRAL-MULTIPLE CHOICE QUESTIONS
- int(0)^(pi//2) sin ^(3) x cos^(3) x" "dx =
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- int(0)^(pi//2) sin ^(2) x cos^(3) x" "dx =
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- int0^(pi/2)sqrt(sinphi)cos^5phidphi
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- int(0)^(pi//2) sqrt(cos x) sin ^(3) x" "dx=
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- int0^pisin^3x(1+2cosx)(1+cosx)^2dx
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- int(0)^(pi//4) sec^(4) x" dx =
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- int(0)^(pi//4) sec^(4) x " " dx =
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- int(0)^(pi//2) (cosx )/ (1+sin^(2)x)dx=
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- int(0)^(pi//2)(sin x) / (1+ cos^(2) x ) dx =
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- int(0)^(pi//2)(sin xcos x) / (1+ sin^(4) x ) dx =
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- Evaluate the following : int(0)^(pi//4)(sec^(2)x)/(tan^(2)x+4 tanx+...
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- int(0)^(pi) dx/(1-2acos x + a^(2)) =
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- int(0)^(pi//4)(sin 2 x)/(sin^(4) x + cos^(4) x ) dx =
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- int(0)^(pi//2) (1+ 2 cos x)/((2+ cosx )^(2) )dx =
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- int(pi//4) ^(3pi//4) dx/((sin x - 2 cosx)(2sin x + cos x))=
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- If I(n) = int (0)^(pi//4) tan^(n) theta " " d theta, "then "I(8)+I(6)=
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- int0^(pi/4) (sinx+cosx)/(9+16sin2x)dx
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- Evaluate the following : int(0)^(pi//2)(1)/(5+4 cos x)dx
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- int (0)^(pi//2) dx/(5+4sinx)=
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- int (0)^(pi//2) dx/(4cosx+9sinx)=
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