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int(0)^(pi//2) abs(sinx-cosx) dx=...

`int_(0)^(pi//2) abs(sinx-cosx) dx=`

A

0

B

`sqrt(2) -1`

C

`2sqrt(2)-2`

D

`2sqrt(2) +2`

Text Solution

Verified by Experts

The correct Answer is:
C
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