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NIKITA PUBLICATION-DEFINITE INTEGRAL-MULTIPLE CHOICE QUESTIONS
- int(0)^(pi//2)log ((1+ sinx)/ (1+ cos x )) dx=
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- int(0)^(1) tan ^(-1) ((2x-1)/(1+x-x^(2)))dx =
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- int0^pixlogsinx dx
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- int0^1log(1+x)/(1+x^2)dx
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- The value of underset(0)overset(oo)int (logx)/(1+x^(2))dx, is
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- int(-a) ^(a) dx/(x+x^(3)) =
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- int(-1) ^(1) x^(2) /(1+x^(2)) dx =
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- int(-1//2) ^(1//2) (1+x^(3)) /(4-x^(2)) dx =
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- int(-1)^(1) (1+x^(3))/(9-x^(2)) dx =
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- int(-1)^(1) (sqrt(1+x+x^(2))-sqrt(1-x+x^(2))) dx =
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- int(-9) ^(9) (x^(3))/(4-x^(2)) dx =
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- Evaluate: int(-a)^a\ sqrt((a-x)/(a+x))\ dx\ \
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- Evaluate: int(pi//4)^(pi//4)(x+pi//4)/(2-cos2x)dx
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- int(-pi)^(pi) (2x(1+ sinx))/(1+ cos^(2))dx is
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- int(-pi//4) ^(pi//4) x^(3) sin^(4) xdx=
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- int(-pi//2) ^(pi//2)sin^(3) xdx=
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- int(-pi//2)^(pi//2)sin^(2)xdx
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- int(-pi//2)^(pi//2)(sin^(4)x)/(sin^(4)x + cos^(4)x)dx=
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- int(-pi) ^(pi) (sin^(4) x) / (sin ^(4) x + cos^(4)x)dx=
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- The value of int(-pi)^(pi) sin^(3) x cos^(2)x dx is"….."
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