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NIKITA PUBLICATION-DEFINITE INTEGRAL-MULTIPLE CHOICE QUESTIONS
- int(-9) ^(9) (x^(3))/(4-x^(2)) dx =
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- Evaluate: int(-a)^a\ sqrt((a-x)/(a+x))\ dx\ \
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- Evaluate: int(pi//4)^(pi//4)(x+pi//4)/(2-cos2x)dx
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- int(-pi)^(pi) (2x(1+ sinx))/(1+ cos^(2))dx is
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- int(-pi//4) ^(pi//4) x^(3) sin^(4) xdx=
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- int(-pi//2) ^(pi//2)sin^(3) xdx=
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- int(-pi//2)^(pi//2)sin^(2)xdx
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- int(-pi//2)^(pi//2)(sin^(4)x)/(sin^(4)x + cos^(4)x)dx=
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- int(-pi) ^(pi) (sin^(4) x) / (sin ^(4) x + cos^(4)x)dx=
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- The value of int(-pi)^(pi) sin^(3) x cos^(2)x dx is"….."
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- int(-pi//4) ^(pi//4) tan^(2) x sec (x)dx =
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- int(-pi//2)^(pi//2) sqrt((1-cos2x)/2)dx =
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- int(-1//2) ^(1//2) (cos x ) log ((1-x)/(1+x)) dx =
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- Evaluate the following : int(-pi//2)^(pi//2)log((2-sinx)/(2+sinx))d...
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- int(-3) ^(3) log ((9-x)/(9+x)) dx=
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- The value int(-2)^(2) (plog ((1+x)/(1-x)) + q log ((1-x)/(1+x))^(-2) +...
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- Evaluate: int(-pi//2)^(pi//2)(cosx)/(1+e^x)dx
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- If int(0)^(alpha) (3x^(2) + 2x + 1) dx = 14, " then " alpha =
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- If int(0)^(pi//2) log(cosx) dx=pi/2 log (1/2), then int(0) ^(pi//2...
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- The Integral int(pi/4)^((3pi)/4)(dx)/(1+cosx) is equal to: ...
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