If a particle covers half the circle of radius R with constant speed then

Options

A. momentum change is mvr
B. chanfe in K.E is `1//2mv^(2)`
C. change in K.E. is `mv^(2)`
D. change in K.E. is zero

Answer

D

Explanation

As momentum is a vector quantity
`therefore` Change in momentum
`Delta P=2mv sin (theta //2)`
`=2mv sin (90)=2mv`
But kinetic energy remains always constant so change in kinetic energy is zero.