If a small babyof mass m is moving with angular velocity `omega` in a circle of radius r, then its K.E. will be

Options

A. `(momega r)/(2)`
B. `(m omega ^(2) r )`
C. `(m omega ^(2) r^(2))/(2)`
D. `(m omega r ^(2))/(2)`

Answer

C

Explanation

`KE=(1)/(2)mv^(2) (v=r omega)`
`therefore KE=(1)/(2) mr^(2) omega ^(2) `
`=(m omega ^(2) r^(2))/(2)`.