A particle of mass M is moving in a horizontal circle of radius R with uniform speed V. When it moves from one point to a diametrically opposite point, its

Options

A. K.E. changes by `mv^(2)//4`
B. momentum does not change
C. momentum changes by 2mv
D. K.E. changes by `mv^(2)`

Answer

C

Explanation

`Delta p = 2p sin theta //2`
`=2mv sin theta //2=2 mv sin 90 =2 mv`.