The angular displacement of a particle performing circular motion is
`theta=(t^(3))/(60)-(t)/(4)`
where ` theta` is in radian and 't' is in second .Then the angular velocity and angular acceleraion of a particle at the end of 5 s will be

Options

A. `1 rad //s, 5 rad//s^(2)`
B. `1 rad//s, 0.5 rad//s^(2)`
C. `5 rad//s, 1 rad//s^(2)`
D. `0.1 rad//s, 5 rad//s^(2)`

Answer

B

Explanation

`(d theta)/(d t)=(3t^(2))/(60)(1)/(4) and (d^(2)theta)/(d t ^(2))= (6t)/(60)`