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If a particle is moving with uniform velocity 20 m//s on a circular track of radius 10 m, then the magnitude of change in velocity in half revolution will be

A

`20 m//s`

B

`10m//s`

C

`30 m//s`

D

`40 m//s`

Text Solution

Verified by Experts

The correct Answer is:
D

`Delta v = 2 v sin (theta )/(2)=2xx20 xx sin 90 `
`=2xx20=40m//s`
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