A particle P is moving in a circle of radius r with a uniform speed u. C is the centre of the circle and AB is diameter. The angular velocity of P about A and V are in the ratio :

Options

A. `1:1`
B. `1:2`
C. `2:1`
D. `4:2`

Answer

B

Explanation

`AC=CP`=radius of the circle
`therefore angle CAP and CPA=theta`.
from` Delta A CP,`
`theta+thetaxx=180`
`therefore xx =180-20 `
`therefore angle BCP=180-x`
` therefore=2theta `
The angular velocity of p w .r t to A is ,
`omega _(PA)=(theta)/(t)`
The angular velocity of Pw.r.t to C is
`omega _(PC)=(2theta)/(t)`
`therefore (omega_(PA))/(omega_(PC))=(theta)/(t)xx(t)/(2theta)=(1)/(2)`