A car is moving in a circular path of radius `500m` with a speed of `30 m//s`. If the speed is increased at the rate of `2 m//s^(2)`, the resultant acceleration will be .

Options

A. `2m//s^(2)`
B. `1.8m//s^(2)`
C. `2.69m//s^(2)`
D. `9.8m//s^(2)`

Answer

C

Explanation

`(v^(2))/(r)=(30xx30)/(500)=(9)/(5)=1.8`
`therefore a_(R)=sqrt(a_(T)^(2)+a_(r)^(2))=sqrt(a_(T)^(2)+((v^(2))/(r))^(2))`