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A particle moves in a circle of radius 2...

A particle moves in a circle of radius 25 cm at two revolutions per sec. The acceleration of the particle in `m//s^(2)` is:

A

`12 pi ^(2)`

B

`8pi^(2)`

C

`4pi^(2)`

D

`2 pi^(2)`

Text Solution

Verified by Experts

The correct Answer is:
C

`a=romega^(2)`
`=r4pi^(2)n^(2)`
`=0.25xx4pi^(2)xx4=4pi^(2)`
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