The acceleration of a point on the rim of a flywheel of diameter 1.2 m, if it makes 900 revolutions per minute, will be

Options

A. `540 pi ^(2) m//s^(2)`
B. `270 m//s^(2)`
C. `360m//s^(2)`
D. `540m//s^(2)`

Answer

A

Explanation

`a_(T)=romega^(2)`