A particle is moving in a circle of radius 20 cm has a linear speed of `10 m//s` at a certain instant and linear speed is increases at the rate of `2m//s^(2)`. What is the rate at which its acceleration in U.C.M. is increasing at that instant?

Options

A. `400 m//s^(2)`
B. `200m//s^(3)`
C. `300m//s^(3)`
D. `100m//s^(3)`

Answer

B

Explanation

`(d)/(dt)((v^(2))/(r))=(2v)/(r) (dv)/(dt)`