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A particle goes round a circular path wi...

A particle goes round a circular path with uniform speed v.After describing half the circle, what is the change in its centripetal acceleration?

A

`(v^(2))/(r)`

B

`(2v^(2))/(r)`

C

`(2v^(2))/(pir)`

D

`(v^(2))/(pir)`

Text Solution

Verified by Experts

The correct Answer is:
B

`Delta a =2a "sin" (theta)/(2)=(2v^(2))/(r)xx1=(2v^(2))/(r) m//s`.
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