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The acceleration of an athlete running a...

The acceleration of an athlete running at 36 kmph when neotiating a turn of radius 25 m is

A

`1 m//s^(2)`

B

`2m//s^(2)`

C

`4 m//s^(2)`

D

`8 m//s^(2)`

Text Solution

Verified by Experts

The correct Answer is:
D
`v=45xx(5)/(18)=(25)/(2)`
`omega=(v)/(r)=(25)/((2)/(0.5))=25 rad//s`
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