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The second 's hand of a watch has length...

The second 's hand of a watch has length 6 cm. Speed of end point and magnitude of difference of velocities at two perpendicular possition will be

A

`6.28 and 0 mm//s`

B

`8.88 and 4.44 mm//s`

C

`8.88 and 6.28 mm//s`

D

`6.28 and 8.88mm//s`

Text Solution

Verified by Experts

The correct Answer is:
D
`v=r omega =(rxx2pi)/(T)=(0.06xx2pi)/(60)=6.28 mm//s` magnitude of change in velocity `=|vecv_(n)-vecv_(1)|`
`sqrt(v_(1)^(2)+v_(2)^(2))=8.88 mm//s (As v_(1)=v_(2)=6.28 mm//s)`
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Knowledge Check

  • The second's hand of a watch has length 6 cm. Speed of end point and magnitude of difference of velocities at two perpendicular positions will be

    A
    `2 pi` & `0 mm//s`
    B
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    C
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    D
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    B
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    D
    `(pi)/(5sqrt(2)and(pi)/(5)cm//s`

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    B
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    C
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