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A particle is moving along a circle of r...

A particle is moving along a circle of radius 3 m .If its centripetal acceleration is `3ms^(-2)` , its angular velocity in` rad s^(-1)` is

A

1

B

`1//3`

C

3

D

0.5

Text Solution

Verified by Experts

The correct Answer is:
A

`a=romega^(2)`
` therefore omega^(2)=(3)/(3)=1`
`therefore omega= 1 "rad" s^(-1)`.
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