If the kinetic energy of a particle moving with a constant speed on a circular path of radius 4 m is 100 j .Then the centripetal force will be

Options

A. 30 N
B. 50 N
C. 40 N
D. 60 N

Answer

B

Explanation

`K.E.=(1)/(2)mv^(2)=(1)/(2)((mv^(2))/(r))r=F_(r)/(2)`
`therefore F=(2E)/(r)`