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A particle of mass m is moving in a hori...

A particle of mass m is moving in a horizontal circle of radius r, under a centripetal force equal to `(-K//r^(2))`, where k is a constant. The total energy of the particle is -

A

`-K//r`

B

`-K//2r`

C

`K//2r`

D

`-2K//r`

Text Solution

Verified by Experts

The correct Answer is:
B
`F=(-K)/(r^(2))`
`KE=(1)/(2)Fr=(1)/(2)(-K)/(r^(2))xxr=-(k)/(2r)`
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