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A 500 kg crave takes a turne of radius 5...

A 500 kg crave takes a turne of radius 50 m wiyh velocity of ` 54 km//h.The centripetal force is

A

1200 N

B

2250 V

C

750 N

D

250 N

Text Solution

Verified by Experts

The correct Answer is:
B
`F=(mv^(2))/(r)=(500xx225)/(50)=2250 N`
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