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If a bodyof mass 1000 gm is tied to free...

If a bodyof mass 1000 gm is tied to free end of string of length 100 cm and whirled in a horizontal circle in a second, then the tecsion in the string will be

A

`4pi^(2) N`

B

`2pi^(2) N`

C

`3pi^(2)N`

D

`pi^(2)N`

Text Solution

Verified by Experts

The correct Answer is:
A
`T=c.p.f.=m r omega ^(2)=m r ((2pi)/(T))^(2)`
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