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A coins kept on a horizontal rotating di...

A coins kept on a horizontal rotating disc has its centre at a distance of 0.25 m from the axis of rotation of the disc .If `mu is 0.2`, then the angular velocity of the disc at which the coion will slip off, `(g=9.8m//s^(2))`

A

`3.8 rad//s`

B

`2.8 rad//s`

C

`4.8 rad//s`

D

`5.8 rad//s`

Text Solution

Verified by Experts

The correct Answer is:
B

`v=sqrt(mu g r )`
`therefore r omega =sqrt mu g r `
`therefore omega = sqrt (mu g)/(r)`
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