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The maximum safe speed of a vehicle over...

The maximum safe speed of a vehicle over a curved road of radius 150 m is `10 m//s`. If the width of road is 7.5 m, the height of the outer edge will be

A

0.25 m

B

0.50 m

C

0.30 m

D

0.60 m

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The correct Answer is:
To solve the problem, we need to find the height of the outer edge of a curved road given the maximum safe speed, radius of the curve, and width of the road. ### Step-by-Step Solution: 1. **Identify Given Values**: - Maximum safe speed (V) = 10 m/s - Radius of the curve (r) = 150 m - Width of the road (l) = 7.5 m 2. **Use the Formula for Maximum Speed**: The maximum speed on a curved road can be expressed as: \[ V_{\text{max}} = \sqrt{\mu \cdot r \cdot g} \] where \( \mu \) is the coefficient of friction, \( r \) is the radius of the curve, and \( g \) is the acceleration due to gravity (approximately 10 m/s² for calculations). 3. **Relate Height to Speed and Road Width**: The height of the outer edge (h) can be calculated using the formula: \[ h = \frac{V^2 \cdot l}{r \cdot g} \] where: - \( V \) is the maximum speed, - \( l \) is the width of the road, - \( r \) is the radius of the curve, - \( g \) is the acceleration due to gravity. 4. **Substitute the Known Values**: Substitute the values into the formula: \[ h = \frac{(10)^2 \cdot 7.5}{150 \cdot 10} \] 5. **Calculate the Numerator**: \[ (10)^2 \cdot 7.5 = 100 \cdot 7.5 = 750 \] 6. **Calculate the Denominator**: \[ 150 \cdot 10 = 1500 \] 7. **Calculate Height (h)**: Now substitute the values into the equation: \[ h = \frac{750}{1500} = 0.5 \text{ m} \] 8. **Conclusion**: The height of the outer edge of the road is 0.5 meters. ### Final Answer: The height of the outer edge will be **0.5 meters**. ---

To solve the problem, we need to find the height of the outer edge of a curved road given the maximum safe speed, radius of the curve, and width of the road. ### Step-by-Step Solution: 1. **Identify Given Values**: - Maximum safe speed (V) = 10 m/s - Radius of the curve (r) = 150 m - Width of the road (l) = 7.5 m ...
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