A car is travelling at 36 kmph on a road . The maximum turning radius of the car is 20 m ans `g=10m//s^(2)` .Then the coefficient of friction between its tyres and the road is

Options

A. `0.2`
B. `0.4`
C. `0.5`
D. `0.8`

Answer

C

Explanation

`v=36xx(5)/(18)=10m//s, r=20m, g=10 m//s^(2), mu=?`
`v=sqrt(mu rg)`
`v^(2)=mu rg therefore mu=(v^(2))/(rg)`
`=(10xx10)/(20xx10)=0.5.`