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A simple pendulum of length 1 m the bob ...

A simple pendulum of length 1 m the bob performs circular motion in horizontal plane if its string making an angle ` 60 ^(@)` with the verticle , then the period of rotation of the bob will be `(g=10 m//s^(2)`

A

`2 s`

B

`1.4 s`

C

`1,98 s`

D

`4 s`

Text Solution

Verified by Experts

The correct Answer is:
B
`T=2pi sqrt((l cos theta)/(g))`
`=2pi sqrt((1xx cos 60)/(10))`
`=2pisqrt((1)/(2)xx(1)/(10))=sqrt2=1.48`.
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