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Each rod of a centrifugal governor is 10...

Each rod of a centrifugal governor is 10 cm long then the number of revolutions per second made when the rod include at an angle of `60^(@)` will be `(g=9.8 m//s^(2))`

A

22

B

49

C

`22//49`

D

`49//22`

Text Solution

Verified by Experts

The correct Answer is:
D
`r=0.1m,n=? theta=60^(@)`
`n=(1)/(2pi)sqrt((g)/(l cos theta))`
`=(1)/(2pi)sqrt((9.8)/(0.1xx(1)/(2)))=(1)/(2pi)sqrt(196)`
`=(14)/(2xx(22)/(7))=(49)/(22)`.
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