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A bob is suspended from an ideal string ...

A bob is suspended from an ideal string makes an angle `60^(@)` to the verticle and whirled along a horizontal circle.Then its perod of revolution is

A

`pi sqrt((l)/(g))`

B

`pisqrt((l)/(2g))`

C

`pi sqrt((2l)/(g))`

D

`2pisqrt((l)/(g))`

Text Solution

Verified by Experts

The correct Answer is:
C
`T=2pisqrt((l cos theta )/(g))`
`=2 pi sqrt((l)/(2g))=pisqrt((4l)/(2g))=pisqrt((2l)/(g)`
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