The vertical section of a road over the bridge is in the from of circle of radius 15.5 m What will be the maximum velocity with which a car whose centre of gravity is 0.5 m above the ground can cross the bridge without losing contact with the surface of bridge at the highest point ? `(g=9.8 m//s^(2))`

Options

A. `10.56 m//s`
B. `12.56 m//s`
C. `14.56 m//s`
D. `1.256 m//s`

Answer

B

Explanation

` mg=(mv^(2))/(r)`
`therefore v=sqrt(rg)=sqrt((15.5+0.5)xx9.8)=12.56`